at an examination in which full marks were 500. a got 10% less than b, b got 25% more than c and c got 20% less than d. if a got 360marks, what percentage of full marks was obtained by d?

at an examination in which full marks were 500. a got 10% less than b, b got 25% more than c and c got 20% less than d. if a got 360marks, what percentage of full marks was obtained by d?

2 months ago 11
Nature

It looks like your question is incomplete, but I can help you analyze the given information and set up the problem based on what you provided.

Given:

  • Full marks of the examination = 100 (assuming "00" means 100)
  • A got 1 less than B
  • B got more than C
  • C got 2 less than D
  • A got 3 (probably 3 less than someone or 3 marks, but this part is incomplete)

Let's denote the marks obtained by each student as:

  • A = a
  • B = b
  • C = c
  • D = d

From the given information:

  1. a=b−1a=b-1a=b−1 (A got 1 less than B)
  2. b>cb>cb>c (B got more than C)
  3. c=d−2c=d-2c=d−2 (C got 2 less than D)

If you can provide the rest of the question or clarify the part about "A got 3...", I can help you solve it further!

Example continuation (if A got 3 less than D):

If the missing part is "A got 3 less than D," then:

  1. a=d−3a=d-3a=d−3

Using these equations, you can express all marks in terms of one variable and solve for each. Would you like me to proceed with this assumption? Or please provide the complete question!

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