To calculate the work done by a pulling force of 40 N, you need to know the distance over which the force is applied and the angle between the force and the direction of displacement. The general formula for work done WWW is:

W=F×d×cos⁡(θ)W=F\times d\times \cos(\theta)W=F×d×cos(θ)

where

• FFF is the magnitude of the force (40 N in this case),
• ddd is the displacement (distance moved by the object),
• θ\theta θ is the angle between the force and the displacement direction.

If the force is applied parallel to the direction of motion (θ=0∘\theta =0^\circ θ=0∘), then cos⁡(0∘)=1\cos(0^\circ)=1cos(0∘)=1 and the work simplifies to:

W=F×dW=F\times dW=F×d

For example, if the force of 40 N pulls an object 8 meters along a horizontal surface at an angle of 60° above the horizontal, the work done is:

W=40×8×cos⁡(60∘)=40×8×0.5=160 JoulesW=40\times 8\times \cos(60^\circ)=40\times 8\times 0.5=160\text{ Joules}W=40×8×cos(60∘)=40×8×0.5=160 Joules

This means the pulling force does 160 Joules of work on the object

. If the angle or distance is different, you can substitute those values accordingly. If the force is in the same direction as displacement, just multiply force and distance. In summary:

• Work done depends on force magnitude, displacement, and the cosine of the angle between them.
• Work = Force × Distance × cos(angle)
• For 40 N pulling force over 8 m at 60°, work done = 160 J.

This formula applies generally for any pulling force and displacement scenario