reena took a loan of rs. 1200 with simple interest for as many years as the rate of interest. if she paid rs. 432 as interest at the end of the loan period, what was the rate of interest?

3 hours ago 3

Let's analyze the problem step-by-step.

SI=P×R×T100SI=\frac{P\times R\times T}{100}SI=100P×R×T

Since the time period TTT is equal to the rate of interest RRR, substitute T=RT=RT=R:

432=1200×R×R100432=\frac{1200\times R\times R}{100}432=1001200×R×R

432=1200R2100432=\frac{1200R^2}{100}432=1001200R2

432=12R2432=12R^2432=12R2

R2=43212=36R^2=\frac{432}{12}=36R2=12432=36

R=36=6R=\sqrt{36}=6R=36=6

The rate of interest is 6%. If you want, I can also help with similar problems or explain the concept of simple interest further!