what is the sum of two consecutive even numbers, the difference of whose squares is 84?

what is the sum of two consecutive even numbers, the difference of whose squares is 84?

1 month ago 32
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Let's solve the problem step-by-step.

Problem Restatement

We want to find the sum of two consecutive even numbers such that the difference of their squares is 84.

Step 1: Define the variables

Let the first even number be xxx.
Since the numbers are consecutive even numbers, the next even number is x+2x+2x+2.

Step 2: Write the equation for the difference of their squares

The difference of their squares is given as 84:

(x+2)2−x2=84(x+2)^2-x^2=84(x+2)2−x2=84

Step 3: Expand and simplify

(x2+4x+4)−x2=84(x^2+4x+4)-x^2=84(x2+4x+4)−x2=84

4x+4=844x+4=844x+4=84

Step 4: Solve for xxx

4x=84−44x=84-44x=84−4

4x=804x=804x=80

x=20x=20x=20

Step 5: Find the two numbers and their sum

The two consecutive even numbers are:

20and2220\quad \text{and}\quad 2220and22

Their sum is:

20+22=4220+22=4220+22=42

Final answer:

The sum of the two consecutive even numbers is 42.

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